Everything You Need to Know About Death Star Orbital Physics

A fully armed and operational physics lesson about ‘Return of the Jedi’

Rhett Allain
OneZero

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Photo: © Lucasfilm Ltd.

ItIt might seem silly to look at the physics from a movie that was released more than 30 years ago, but here we are. Yes, Star Wars: Return of the Jedi was first in the movie theaters back in 1983. So, why does it even matter? Well, first, it matters to me because I’m a huge Star Wars fan. Second, it seems like the Death Star from Return of the Jedi (or at least pieces of it) shows up in the upcoming Star Wars: The Rise of Skywalker.

So, let’s think about the physics of the Death Star II. Here is a quick refresher: The emperor is building a new (and slightly bigger) Death Star. Hopefully, this time it doesn’t have the vulnerable ventilation shaft — but who knows. While it’s under construction, the Death Star orbits the planet moon of Endor. You see, Endor has this bitchin’ shield generator that the Imperials project from the moon’s surface to protect the space station.

That’s it for the plot — now for the physics. I’m going to assume that the Death Star is in a geostationary orbit around Endor. That means that the space station is not flying under its own power, but is instead just moving due to a gravitational interaction. The geostationary part means that the orbital…

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Rhett Allain
OneZero
Writer for

Physics faculty, science blogger of all things geek. Technical Consultant for CBS MacGyver and MythBusters. WIRED blogger.